# Determine the slope of the line 8x - 32y -9 = 0?

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We have to find the slope of the line 8x – 32y -9 =0.

First we express the equation in the form y = mx+c, where m is the slope of the line and c is the y-intercept.

8x – 32y -9 =0

keep y on one side and move x and the constant to the other side

=> -32y = 9-8x

divide both the sides by -32

=> y = (9/-32) + (8/32) x

simplify all the factors

=> y = -9/32 +x/4

Therefore we get that m = 1/4 for the given equation.

**The required slope is 1/4.**

The slope of an equation in the form y = mx+c is m.

So the given equation 8x - 32y -9 = 0 can be rewritten by subtracting (8x-9) as:

-32y = -8x+9. Dvide by -32 and we get:

y = (-8/32)x+9/-32)

y = (1/4)x - 9/32

Identify the above equation with y = mx+c, we get m = 1/4.

Therefore the slope of the given equation is slope = 1/4.