# Determine the particular value and the parameter k so that kx-y=3k-6 has the x-intercept of 5.

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The given equation is `kx-y=3k-6.`

It has the x-intercept of 5. So, putting x=5 and y=0 in the above equation we get:

`k*5-0=3k-6`

`rArr 2k=-6`

`rArr k=-3`

Now, plugging the value of k in the above equation we get:

`-3*x-y=3*-3-6`

`rArr y=-3x+15`

This is the equation of a straight line where -3=k is the slope of the line.

Thanks :)