Determine the oxidation number for O2 in the following redox reaction.   CH4+O2-->CO2+H2O



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You need to remember that usually, the oxidation number of oxygen in any compound, excepting `BaO_2` , is -`2` , hence, in the given redox reaction the oxygen is reduced from 0 to -2 state.

You need to place the oxidation number above each element in redox reaction, such that:

-4 +1        0      +4  -2       1    -2

`C H_4 + O_2 -> C O_2 + H_2 O`

Since the oxidation number of O decreases from 0 to -2, then the oxygen is reduced in the given redox reaction.

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