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Determine one variableIf ln t= -ln2 what is t ?
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First of all, we'll impose the constraints of existence:
ln t= -ln2
We'll use the power property of logarithms:
ln t = ln 2^-1
ln t = ln 1/2
Since the bases are matching, we'll use the fact that the logarithmic function is injective and we'll get:
t = 1/2 > 0
Posted by giorgiana1976 on February 8, 2011 at 11:05 AM (Answer #2)
High School Teacher
ln t = - ln 2
We will preview the properties of the logarithm equations.
We know that: ln a^b = b*ln a
Then we will rewrite the equation.
- ln 2 = -1 * ln 2 = ln 2^-1 = ln (1/2)
==> ln t = ln (1/2)
Now we have the logarithms are equal, then t= 1/2
Then the answer is t = 1/2
Posted by hala718 on February 8, 2011 at 8:31 PM (Answer #3)
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