determine the equation of the line tangent to the graph of  `y=14e^(9x)` ` `

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tiburtius | High School Teacher | (Level 2) Educator

Posted on

Equation of a tangent line at point `(x_0,y_0)` to the graph of `y=f(x)` is


So let's calculate `f'(x)`


Hence equation of the tangent line at the point `(x_0,y_0)` is


For example equation of the tangent line at point (0,14) would be



Blue is your function `y=14e^(9x)` and red is the tangent line at point (0,14).

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oldnick | (Level 1) Valedictorian

Posted on



`y-y_0=126e^(9x) (x-x_0)`

`y=126x e^(9x_0)-126x_0 e^(9x_0)+y_0`

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