Describe what you would see: Iron+copper(2) sulfate solution and zinc+lead(2) nitrate solution



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Posted on (Answer #1)

Iron is more reactive than `Cu` . So Cu in `CuSO_4` will be displaced by `Fe^(2+)` in iron.

`Fe+CuSO_4 rarr FeSO_4+Cu`

Initially the solution will look like blue because of `CuSO_4` . But when `Cu` was replaced by `Fe` then `Cu` will be precipitate as a thin layer. We can see it by the change of colour from blue to red in the solution.


As explained in the early part `Pb` in `Pb(NO_3)_2` will be displaced by `Zn` .

`Zn+ Pb(NO_3)_2 rarr Zn(NO_3)_2+Pb`

We can see crystals of Pb forming on Zn.




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