derivative y=sin(e^(3x-x^2))? show how



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Posted on (Answer #1)

You need to use chain rule to find derivative of function.

The chain rule tells that you need to differentiate with respect to x, from outside toward inside, such that:

`dy/dx = (sin(e^(3x-x^2)))'*(e^(3x-x^2))'*(3x-x^2)'`

`dy/dx = (cos(e^(3x-x^2)))*(e^(3x-x^2))*(3- 2x)`

Hence, the derivative of function is `dy/dx = (3- 2x)*(e^(3x-x^2))*(cos(e^(3x-x^2)))`

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