Demonstrate the identity `a_(n+1)-a_n = 2` if `a_(n)=2n+3` ?
1 Answer | Add Yours
It is given that `a_n = 2n + 3`
The identity `a_(n+1) - a_n = 2` has to be proved.
`a_(n+1) - a_n`
= `2(n + 1) + 3 - (2n + 3)`
= 2n + 2 + 3 - 2n - 3
This proves that `a_(n+1) - a_n = 2` if `a_n = 2n + 3`
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes