# On a dark and lonely night, a man is standing 5 meters away from a streetlight. The man is 2 meters tall and the light is 6 meters high. How longis the man's shadow?

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Please refer the attached image with the explanations.

The notation is as follows

BC = light post height

DE = height of man

AD = length of shadow

Using sine law we can say;

`(DE)/(BC) = (AD)/(AB)`

`2/6 = x/(5+x)`

`2(5+x) =6x`

`10 = 4x`

`x = 2.5`

*The shadow of man is 2.5m long.*

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