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On a dark and lonely night, a man is standing 5 meters away from a streetlight. The man...

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christiano-cr7 | Salutatorian

Posted October 1, 2013 at 2:58 AM via web

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On a dark and lonely night, a man is standing 5 meters away from a street
light. The man is 2 meters tall and the light is 6 meters high. How long
is the man's shadow?

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted October 1, 2013 at 3:04 AM (Answer #1)

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Please refer the attached image with the explanations.

The notation is as follows

BC = light post height

DE = height of man

AD = length of shadow

Using sine law we can say;

`(DE)/(BC) = (AD)/(AB)`

`2/6 = x/(5+x)`

`2(5+x) =6x`

`10 = 4x`

`x = 2.5`

The shadow of man is 2.5m long.

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