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A CuSO4  solution is electrolyzed for 20. minutes with a current of 2.0 ampere. What...

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lak-86 | Student, Undergraduate | Salutatorian

Posted August 1, 2013 at 10:27 AM via web

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A CuSO4  solution is electrolyzed for 20. minutes with a current of 2.0 ampere. What is the maximum mass of copper that could be deposited?

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llltkl | College Teacher | Valedictorian

Posted August 1, 2013 at 10:53 AM (Answer #1)

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According to Faraday’s first law of electrolysis, the mass of a substance getting deposited at the cathode is proportional to the quantity of charge passing through the solution.

`m prop Q`

`m prop I*t`

`m=Z*i*t`

For copper, Z = Eqv. Wt./Faraday=31.75/96500

Plugging in the values,

m=31.75*20*60*2/96500

=0.79 g

Therefore, the maximum mass of copper that could be deposited by passing a current of 2 amp. for 20 min. through a CuSO4 solution is 0.79 g.

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