Better Students Ask More Questions.
Could you please explain how you would use vector projection to find the closest...
1 Answer | add yours
High School Teacher
Let the two skew lines have equations
(x - x1)/ l1 = (y - y1)/m1 = (z - z1)/n1
(x - x2)/ l2 = (y - y2)/m2 = (z - z2)/n2
Then the shortest distance between the two is given by
D = A/B
where A = (x2-x1)(m1n2-n1m2)-(y2-y1)(l1m2-l2m1)+
and B = sqrt( (m1n2-m2n1)^2 + (n1l2-n2l1)^2 +(l1m2-l2m1)^2)
Posted by santaone on September 12, 2011 at 12:07 AM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.