If cos x = 1/2 square root of 3, find sin x.
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cos x = (1/2)*sq root of 3.
The fundamental formula of trigonometry says:
sin^2 (x) + cos^2 (x)=1
sin x = sq root of [1-cos^2 (x)]
sin x = sq root of (1 - 3/4)
sin x = sq root of (1/4)
sin x = 1/2
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