# If cos^2 x - 6*sin 2x = 0 what is one value of x?

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One value of x is required for which `cos^2(x) - 6*sin 2x =0`

`cos^2(x) - 6*sin 2x =0`

=> `cos^2(x) -12*sin x*cos x = 0`

=> `cos x(cos x - 12*sin x) = 0`

=> `cos x = 0 and cos x = 12*sin x`

cos x = 0

=> x = 90

**One value of x for which cos^2(x) - 6*sin 2x =0 is x = 90 degrees**