Better Students Ask More Questions.
If cos^2 x - 6*sin 2x = 0 what is one value of x?
1 Answer | add yours
One value of x is required for which `cos^2(x) - 6*sin 2x =0`
`cos^2(x) - 6*sin 2x =0`
=> `cos^2(x) -12*sin x*cos x = 0`
=> `cos x(cos x - 12*sin x) = 0`
=> `cos x = 0 and cos x = 12*sin x`
cos x = 0
=> x = 90
One value of x for which cos^2(x) - 6*sin 2x =0 is x = 90 degrees
Posted by justaguide on March 28, 2012 at 3:12 AM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.