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Coordinate geometry...Find the ratio in which the line joining A(6,5) and B(4,-3) are...
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First of all, we have to find out the equation of the line AB, in order to express the condition of intersecting 2 lines, which is: the coordinates of the point M, resulted from the intersection between lines AB and y=2, have to verify the equations of the 2 lines :AB and Y=2.
In order to find out the equation of the line AB:
(xB-xA)/(x-xA) = (yB-yA)/(y-yA)
Now, we'll substitute the values of known coordinates:
(4-6)/(x-6) = (-3-5)/(y-5)
-2/(x-6) = -8/(y-5)
After dividing by (-2):
1/(x-6) = 4/(y-5)
y=4x-19, this being the eq. for the line AB.
The M point belongs to AB, only if it's coordinates verifies the equation of the line AB.
By substituting yM=2 into yM=4xM-19, the result will be:
M point coordinates are xM=21/4 and yM=2.
Now we have to find out the length of the segment AB and segment AM, in order to decide the ratio the line AB is split by the line y=2.
The AM segment's length:
AM= sqrt[(21/4 - 6)^2 + (2-5)^2]
AB= sqrt[(xB-xA)^2 + (yB-yA)^2]
AB= sqrt[(4-6)^2 + (-3-5)^2]
MB=AB-AM=2sqrt17 - 3sqrt17/4
The ratio is : AM/MB=(3sqrt17/4)/(5sqrt17/4)
To find out the coordinates for P, we have to remember again the condition that P coordinates has to verify the equation for AB line also.
But yP=0, because P is placed on x axis, so:
P coordinates are: xP=19/4 and yP=0
Posted by giorgiana1976 on February 15, 2010 at 1:22 AM (Answer #1)
High School Teacher
The line Joining (a,b) and (c,d)) is given by:
y-c = (d-b)/(c-a)[x-a]
So, the line Joining A(6,5) and B(4,-3) is given by:
y-5 =(-3-5)/(4-6)(x-6) . Or
y = 4(x-6)+5..................(1).The line y = 2 cuts this line at x1 given by 2= 4(x1-6)+5. Or x1 = (2-5+24)/4 = 5.25. Therefore the coordinates of the points of intersection of the line y =2 and the line AB is at C(5.25,2).
Therefore, if the Ratio of AC and CB is k:1, then ki given by:
(k*4+1*6)/(k+1) = 5.25 or
6-5.25= 5.25k-4k Or 0.75 = 1.25k Or k = 3/5.
So AC:CB = K:1 = 3/5:1 Or 3:5.
The equation of the line AB as at (1) is y = 4(x-6)+5 should intersect the line x axis or y=0 at a point P(x' , 0) given by:
4x' = 24-5 =19 Or
x' = 19/4 = 4.75
Therefore the interesecting point of the line AB and X axis is P whose coordinates are (4.75,0).
Posted by neela on February 15, 2010 at 3:01 AM (Answer #2)
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