Consider the collision of two identical parti-
cles, with m1 = m2 = 10 g.
The initial velocity of particle 1 is v1 and
particle 2 is initially at rest, v2 = 0 m/s..
After an elastic head-on collision, the final
velocity of particle 2 is v′2 and given by?
a. v′2 = 0
b. v′2 = v1
c. v′2 =2 v1/3
d. v′2 =v1/2
e. v′2 =5 v1/3
f. v′2 =4 v1/3
g. v'2 = 2 v1
h. v′2 =3 v1/4
i. v′2 =v1/3
1 Answer | Add Yours
v'2 = v1 is the right answer. The choice b is correct.
A proof is given as follows:
By consevation of momentum and kinetic energy we obtain the following 2 equations.
10v1 = 10v1'+10v2'
Solve these simple two simultaneous equtions for v1'f and v2'f the final velocity of the first and 2nd particle.
Then we get the solutions: v1' = 0 and v2' = v1. That is ,two perfect elastic bodies, when one is at motion with a velocity of v1 collides with another other with equal mass body at rest, the first comes to rest imparting its entire velocity v1 to the 2nd.
We’ve answered 317,752 questions. We can answer yours, too.Ask a question