concrete slab in the shape of a regular octagon. The distance from the centerup one of the peaks is 15 cm. Determine the area of a concrete slab
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Each interior angle of octagon= 135 degree.
`(angle s= ((n-2)xx180)/n)`
Draw a perpendicular from O to side of octagon ON .M is one vertex of octagone.
consider triangle OMN , OM=15 cm,
`angle M=(1/2)` of interior angle f octgon
`MN= 15xx cos(62.5^o)`
`area of DeltaOMN=(1/2) xxMNxxON`
`` area of octagn=`16xx(1/2)xx(15^2) sin(62.5^o) cos(62.5^o)`
`=636.40 ` sq cm.
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