Compare 3*tg 2 to 2*tg 3!
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We'll use a consequence of Lagrange's theorem which says that a function is increasing if it's first derivative is positive.
Let's consider a function f(x)=tg x/x, where x is in the set (0, 3pi/180).
To analyze if we have an increasing function, we have to calculate the first derivative. We've noticed that the function is a fraction and we'll calculate it's derivative following this rule:
(tg x/x)'= [(tg x)'*x-(tgx)*x']/x^2
(tg x/x)' = [(x/cos^2 x) - sin x/cosx]/x^2
(tg x/x)' = (2x-2sinx cosx)/2*x^2*cos^2x
It's obvious that (2x - sin 2x)/2*x^2*cos^2x>0, so f(x) is increasing, so that, for 2pi/180<3pi/180,
pi(radians)=180(degrees) represents the same measure of an angle, so we'll reduce pi with 180
We'll cross multiplying and the result will be
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