# Calculate the common population variance for the following data (to at least three places of decimals) The common population variance to at least 3 places of decimals =Calculate the common...

Calculate the common population variance for the following data (to at least three places of decimals)

The common population variance to at least 3 places of decimals =

Calculate the common population variance for the following data (to at least three places of decimals)

The mean number of flowers per plant for Sample 1 = 6.44 and Sample 2 = 7.20

The estimated population standard deviation of number of flowers per plant Sample 1 = 1.51 and Sample 2 = 1.80

And Sample size for Sample 1 = 9 and Sample 2 = 20

The common population variance to at least 3 places of decimals =

sciencesolve | Teacher | (Level 3) Educator Emeritus

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You should follow the next steps to find the variance of population such that:

find the mean of sample 1: `x = 6.44`

find the deviation from the mean of sample 1: `barx = 1.51`

evaluate `(x - barx)^2 = (6.44 - 1.51)^2 = 24.3049`

divide by degree of freedom: sample size - `1 = 9 - 1 = 8`

You may evaluate the variance of sample 1 such that:

`sigma^2= ((6.44 - 1.51)^2)/8`

`sigma_1^2 = 3.038`

You need to find the mean of sample 2: `x = 7.20`

find the deviation from the mean of sample 1: `barx = 1.80`

evaluate `(x - barx)^2 = (7.20-1.80)^2 = 29.16`

divide by degree of freedom: sample size - 1 = `20 - 1 = 19`

You may evaluate the variance of sample 2 such that:

`sigma^2 = ((7.20-1.80)^2)/19 =gt sigma_2^2 = 1.534`

Hence, evaluating the variance of sample 1 and sample 2 yields `sigma_1^2 = 3.038`  and `sigma_2^2 = 1.534` .

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