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A common hydromenter with astem of 10cm long and volume one-tenth of whole hydrometer,...
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For water the total length submerged is `L_1=10-2 =8cm`. For the second liquid, the total length submerged is `L_2 =10-4 =6 cm` .
The hydrometer works on Archimedes principle, so that the buoyant force is equal to the weight of the liquid corresponding to the volume submerged.
Since the mass of the hydrometer is the same in both cases, the buoyant force needs to be the same:
Here above `L*S` is the volume of the hydrometer that is submerged in liquid. Therefore
`rho_2 =rho_1*L_1/L_2 =1000*8/6 =1333 (kg)/m^3`
Answer: The density of the second liquid is `rho = 1333 (kg)/m^3`
Posted by valentin68 on October 31, 2013 at 5:39 PM (Answer #1)
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