1 Answer | Add Yours
The coin is weighted so that a head is twice as likely to occur as a tail.
When the coin is flipped, the probability of getting heads is 2/3 and the probability of getting tails is 1/3.
If the coin is flipped 10 times, the probability that both heads and tails occurs is equal to 1 - (probability that only heads occurs) - (probability that only tails occurs) = `1 - (2/3)^10 - (1/3)^10 ~~ 0.9826`
The required probability that both heads and tails occurs is approximately 0.9826
We’ve answered 331,205 questions. We can answer yours, too.Ask a question