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A coil made of wire of copper, with wire's diameter d, traversed by a current I, is...
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We'll consider a spiral element, which comprises a central angle dt. The electromagnetic force is acting on the element, dF=l*ds*B; also the stresses T, from the bottoms, are acting on the element. The resultant of both stresses is centripetal:
2*T*sin(dt/2)=2*T*(dt/2)=T*dt , ( (sindx)/dx=1)
The resultant is balancing the force dF, which is centrifugal:
On the other hand,T=sigma*S=sigma*(pi*d^2/4)
so that, B=T/(I*R)=(pi*d^2/4)*sigma/(I*R)
The usual magnetic fields are B<10T
Posted by giorgiana1976 on July 8, 2009 at 3:14 AM (Answer #1)
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