A coffee-cup calorimeter is filled with 50 mL water at 25°C (density = 0.997 g/mL). A 36.5-gram sample of mettalic material is taken from water boiling at 100°C and placed in calorimeter. The equilibrium temperature of the water and sample is 32.5°C. The calorimeter constant is known to be 1.87 J/°C. Calculate the specific heat of the mettalic material. The specific heat of water is 4.184 J/g-°C

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Heat loss= Heat gain

Heat gain by coffee cup calorimeter=`50xx.997xx4.187xx(32.5-25)`

`=1565.414625 C` (i)

Heat loss by metalic body with specific heat S=36.5 x S x (100-32.5)

=2463.75 S C (ii)

from (i) and (ii)

`2463.75S=1565.414625`

`S=.635378843` J/g C

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