Homework Help

# The coefficient of friction between a box and an inclined plane is 0.3639. If the slope...

Student

Kindergarten

Salutatorian

• Up
• 1
• Down

The coefficient of friction between a box and an inclined plane is 0.3639. If the slope of the plane with the horizontal is increased to 45 degrees, what is the acceleration of the box.

Posted by mikerhyme on September 21, 2013 at 2:57 PM via web and tagged with friction, science

College Teacher

(Level 2) Distinguished Educator

• Up
• 1
• Down

The coefficient of friction between a box and an inclined plane is 0.3639.

Let the mass of the box be M. The slope of the plane with the horizontal is equal to 45 degrees. There is a gravitational force on the box in the vertically downward direction. This is equal to M*g. The components of this force in a direction parallel to the plane and perpendicular to the plane are M*g*sin 45 and M*g*cos 45.

The frictional force on the box is M*g*cos 45*0.3639. The net force on the box is M*g*sin 45 - M*g*cos 45*0.3639. The resulting acceleration of the box is `9.8*(1/sqrt 2) - 9.8*(1/sqrt 2)*0.3639` = 4.407

The box accelerates down the inclined plane at 4.407  m./s^2

Posted by justaguide on September 21, 2013 at 3:04 PM (Answer #1)