If 10% students read both, find the probability that a student selected at a random reads either marathi or english newspaper?

In a class of 60 students, 50% students read marathi newspapers and 20% read english newspaper.

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This is a good problem to use a Venn diagram:

There are a total of 60 students. 50% (30 students) read marathi, 20% (12 students) read english, while 10% (6 students) read both.

The Venn diagram would consist of a rectangle with 2 overlapping circles. The circles should be labelled marathi and english. The number in the marathi circle is 24, the number in the intersection is 6, and the number in the english circle is 6. The number outside the circles is 24 (the number of students who read neither marathi or english papers.)

Assuming that the question is the inclusive or ( a student could read marathi, english or both) the probability that a randomly selected student reads marathi or english is `36/60=60%` .

(There are a total of 60 students; 24 read marathi only, 6 read english only, and 6 read both so 36 students read marathi or english.)

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**The probability that a randomly selected student reads marathi or english is 60%**

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Note that 24/60 or 40% read marathi only, 10% read english only, 10% read both and 40% read neither.

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