A chlorine ion (Cl^- ) with a mass of 5.85*10^-26 kg is projected with an energy of 8.50 keV perpendicularly into a magnetic field with a strength of 0.650 T.
A. what is the kinetic energy of the chlorine ion, in joules?
B. what is the speed of the chlorine ion?
For A, I got 1.36*10^-15 J
I don’t know how to figure B...Help please? Is a correct?
1 Answer | Add Yours
Your answer for letter A is correct!
For the next question, we can use the formula for the kinetic energy:
`KE = 1/2 mv^2`
To solve for the speed of the chlorine ion, we should arrange the formula a little bit.
`2 KE = mv^2`
`(2 KE)/(m) = v^2`
`sqrt((2 KE)/(m) = v^2)`
`v = sqrt((2 KE)/(m))`
- KE = `1.36x10^-15 Jou l es or (kg*m^2)/(s^2)`
- m = `5.85x10^-26 kg`
`v = sqrt((2 * (1.36*10^-15))/(5.85x10^-26))`
`v = 215, 628.674 m/s or 2.16x10^5 m/s` -> final answer
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