A charge of q=4.6*10^-6 moves in an electic field between two points with potential difference 2000. What is the work A it has done?

Topic:

Science

Asked on

1 Answer | Add Yours

kjcdb8er's profile pic

Posted on

To answer this question remember that the definition of an electric field potential is based on the amount of work that is required to move a charge q from one point to another. So your work A = q(Va - Vb). The problem statement says that the potential difference Va - Vb is 2000J/C.

Note, that J is a unit of energy, not a potential difference. Joules/Coulomb is another way to say Volt. So if you meant a potential difference of 2000 Volts, then this answer makes sense. Otherwise, the question needs to make more sense.

Also, note that it doesn't matter if the charge travels in a straight line, or takes a meandering path to arrive at the destination point. An electric field is a conservative field, which means that the energy used to get from one point to the other is independent of path.

A = q*2000 = 4.6e-6 [J/C] * 2000 [C] = 9.2e-3 J

We’ve answered 301,737 questions. We can answer yours, too.

Ask a question