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On a certain sum of money, the difference between the compound interest for a year,...
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- Compound interest: `A = P (1 + 0.08/2)^(1times 2)`
High School Teacher
The formulae for compound interest and simple interest:
`A= P(1+i)^n` and `A=P(1+ i n)`
A is the future amount. P is the present amount (which is what we need) i = interest and n= months/ years.
By using a form of simultaneous equations, we will be able to deduce the amount borrowed.
Remember that the interest is a percentage so always divide by 100 (`8/100= 0.08` ).We have divided by 2 because the interest is compunded half yearly (ie twice a year) and we have multiplied n (1 year) by the same 2 that we divided the interest by.
(In other words had it been compounded monthly we would have divided the interest by 12 and would have multiplied n by 12)
2. Simple interest: `A= P(1+0.08 times 1)`
we are working with only 1 year and there is now compounding so n=1
Now we know that the difference is Rs 16. So if we subtract the simple interest from the compound interest formula (ie 1. - 2.) we can deduce the amount originally saved:
`P (1.0816) - P(1.08) = 16`
`therefore 0,0016P = 16`
`therefore P = 16 / 0.0016`
`therefore P = 10 000`
Therefore the amount that was lent out is Rs 10 000
Posted by durbanville on April 24, 2013 at 6:06 AM (Answer #1)
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