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A centrifuge, r = 0.06 cm, revolves at 24000 rpm. If its tensile strength is 120000 N,...
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The centrifuge rotates at 24000 rpm. The radius of the centrifuge is 0.06 cm. A mass is held with a tensile strength of 120000 N. The maximum mass that can be held has to be determined.
The speed of rotation of the centrifuge in terms of rad/s is `(24000*2*pi)/60` = 2513.27412 rad/s. The radius of the centrifuge is 0.06 cm = 0.0006 m. The centrifugal force acting on a mass M is given by M*0.0006*(2513.27412)^2 = 3789.92*M N.
Equating the centrifugal force acting on the mass to the tensile strength gives: M*0.0006*(2513.27412)^2 = 120000
=> M = 31.66 kg
The maximum mass that can be held in the centrifuge is 31.66 kg
Posted by justaguide on April 7, 2013 at 5:09 PM (Answer #1)
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