# Simplify: (2y+4) (3y+1) + (y+1) (2y-4)

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The expression (2y+4)(3y+1) + (y+1)(2y-4) has to be simplified.

(2y+4)(3y+1) + (y+1)(2y-4)

=> 6y^2 + 2y + 12y + 4 + 2y^2 + 2y - 4y - 4

=> 8y^2 + 12y

**The simplified form of (2y+4)(3y+1) + (y+1)(2y-4) is 8y^2 + 12y**

(2y +4)*(3y+1)+(y+1)(2y-4)

= [(6ysquare+2y)+(12y+4)]+[(2ysquare-4y)+(2y-4)]

=**8ysquare+10y**

is the answer

hope it helps u

cheers!!!

just like how you would do above, all you do is simplify the numbers and letters that are the same. if you do the opposite, it will not work therefore, that answer will remain the same.

((2y+4)(3y+1)) + ((y+1)(2y-4))

distribute the terms above to the other parenthesis you should end up with:

6y^2 + 2y + 12y + 4 + 2y^2+ 2y - 4y - 4

combine like terms and you should end up with:

8y^2 + 12y

((2y+4)(3y+1)) + ((y+1)(2y-4))

distribute the termsĀ

6y^2 + 2y + 12y + 4 + 2y^2+ 2y - 4y - 4

combine like termsĀ

8y^2 + 12y