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Can someone give me a crash course on trigonometry?

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parama9000 | Student, Grade 11 | (Level 1) Valedictorian

Posted March 31, 2013 at 2:53 AM via web

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Can someone give me a crash course on trigonometry?

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pramodpandey | College Teacher | (Level 3) Valedictorian

Posted March 31, 2013 at 6:15 AM (Answer #1)

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Givin complete course discription on trignometry  in one or two class is

never possible to any one.

In right angle triangle ABC ,let one angle  A is x and its complement B is 90-x and  angle C is 90.

SinA=(BC/AB)

CosB=(AC/AB)

TanA=(BC/AB)

These are called trignometric ratios.

Also there are reciprocal to these ratios.

Sin^2A+Cos^2A=1

Tan^2A+1=Sec^2A

Cot^2A+1= Cosec^2 A

These are basics ,more detail you can ask questions.

 

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