calculations show that 50% of wood underwater...experimental it shows that 45% underwater..why is there a difference?
(density and buoyance) is it the water is not pure or something else? Thank you CALCULATION- mass 24g...length 6cm..width 4cm.. height 2cm D=M/V=O.5 50% EXPERIMENTAL-0.9 underwater =0.9/0.2height=45%
1 Answer | Add Yours
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes