Solve 2x+3y=7 3x+2y=4 for x and y.
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The values of x and y have to be determined given that :
2x+3y=7...(1)
3x+2y=4...(2)
2*(2)  3*(1)
=> 3*x*2 + 2*y*2  3*2*x  3*y*3 = 4*2  3*7
=> 6x  6x + 4y  9y = 8  21
=> 5y =  13
=> y = 13/5
substitute in (1)
=> 2x + 3*(13/5)=7
=> x = (7  39/5)/2
=> 4/10
=> 2/5
The required value of x = 2/5 and y = 13/5
mmm it's vaary easy
2x+3y =7........equation 1
3x+2y =4............................eq.2
now, multiplying 3 with eq.1 & 2 with eq. 2 we get
6x+9y =21
6x+4y =8

____________
5y =13
or y =13/5
now solve x using the value of y
hey..!!
2 x + 3y = 7 .....(1) multiply by 3
3x + 2y = 4 ..........(2) multiply by 2
from (1)
6x + 9y = 21 ........(3)
from (2)
6x + 4y = 8 .....(4)
(3)(4)
6x + 9y = 21
6x + 4y = 8
() () ()
solve it further .. u'll get y = 13/5
nw.. from (1)
2x + 3*13/5 = 7
2x + 39/5 = 7
2x = 7/1  39/5
2x = 4/5
x = 4/5*2
x = 2/5
u can verify it too...!!
see.. m verifying...!!
=2*2/5 + 3*13/5
= 4/5 + 39/5
= 35/7
=7
hence.. its right...!!
hope i helped.... :)