Calculate the volume of steam produced.

100 mL of methane and 100 mL of oxygen were mixed together and the mixture was sparked. The equation for the combustion reaction is:

CH4 (g) + 2O2 (g) à CO2 (g) +2H2O (g)

All gases are measured at the same temperature and pressure. Under these conditions, water is in the gas state.

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Based on your balanced chemical equation, you know that for every mole of oxygen, you will produce one mole of water vapor. You also know that all the reactants and products are at the same temperature and pressure.

So if you start with 100 mL of oxygen, that is equal to 100 mL/22,400 mL/mole, or 0.003267 moles of oxygen. (One mole of any gas occupies a volume of 22.4 L. This is at STP, but since there is no change in temperature, you can use this figure).

To find the volume of steam (gaseous water), multiply the moles of water (0.003267) times 22,400 mL and you find it is 100 mL.

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