Calculate the volume of the product CO2.

Calculate the volume of carbon dioxide gas produced, at SLC, when 5.00 g of calcium carbonate is added to a solution containing 5.00 g of nitric acid.

### 1 Answer | Add Yours

**First**: write a balanced chemical equation so you can see the mole ratios of reactants and products.

2 HNO3 + CaCO3 --> 2 Ca(NO3)2 + HOH + CO2

**Second:**

Calculate the moles of each reactant to determine if one is a limiting reactant.

moles of CaCO3 = 5g/molar mass of CaCO3

moles of HNO3 = 5 g/molar mass of HNO3

**Third:**

From your results in step 2, you will see that HNO3 is the limiting reactant.

**Four:**

Based on the information from step 3, and the balanced chemical equation in step 1, you know that for every 2 moles of HNO3 you will produce 1 mole of CO2, so find number of moles of CO2 produced.

**Five:**

You know that at STP, 1 mole of CO2 has a volume of 22.4 L. Since you know the moles of CO2 from step 4, calculate the volume of gas produced.

**Six:**

Using Charles's Law, calculate the volume of the gas at SLC, using the volume from step 5, and knowing that the temperature is increasing from 273.1 to 298.1 K.

**Sources:**

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes