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Calculate the value of ΔG° = -RTlnK where T = 298K and lnK = 3.19Here is the link...

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lillupon | Student, Grade 11 | (Level 2) eNoter

Posted May 28, 2012 at 4:14 AM via web

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Calculate the value of ΔG° = -RTlnK where T = 298K and lnK = 3.19

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thilina-g | College Teacher | (Level 1) Educator

Posted May 28, 2012 at 6:02 AM (Answer #1)

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`DeltaG^o` is the Gibbs free energy.

`DeltaG^o = -RTlnK`

 

`R = 0.0083144621 kJK^(-1)mol^(-1)`

`DeltaG^o = -0.0083144621 kJK^(-1)mol^(-1) xx 298 K xx 3.19`

`DeltaG^o = -7.903 kJmol^(-1)`

 

Therefore, the gibbs free energy difference is -7.903 kJ/mol

 

 

 

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