1 Answer | Add Yours
The reaction for which we have to find the enthalpy change is: C2H3OH(l)-->CH3OCH3(l)
The Enthalpy of formation of C2H3OH(l) is given as DHo=-1234.7 kJ and the enthalpy of formation of CH3OCH3(l) is given as DHo=-1328.3kJ.
For a reaction A --> B, the enthalpy change DH of the reaction is given by DHb - DHa
Using the values we have here, DHb = -1328.3 kJ and DHa = -1234.7 kJ, DH of the reaction is -1328.3 - (-1234.7) = -1328.3 + 1234.7 = -93.6 kJ.
The change in enthalpy when the reaction C2H3OH(l)-->CH3OCH3(l) occurs is -93.6 kJ. As the change in enthalpy, DH is negative for this reaction, it is an exothermic reaction that releases heat when it takes place.
We’ve answered 317,752 questions. We can answer yours, too.Ask a question