# calculate the slope of the line 50x + 25y - 5 = 0

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First, we'll put the given equation in the standard form:

y=mx + n, where m represents the slope.

50x + 25y - 5 = 0

We'll isolate 25y to the left side:

25y=-50x+5

We'll divide by 25 both sides:

y=(-50/25)x + 5/25

The standard form of the equation is:

**y = -2x + 1/5**

**The slope of the line 50x + 25y - 5 = 0 is m = -2.**

50x+25y-5=0

If you put this problem into slope-intercept form (y=mx+b) you will have the slope of your equation.

Start by adding five to both sides.

50x+25y=5

Then subtract 50x to both sides. Now your problem is in the correct format, but 'y' isn't alone yet.

25y=-50x+5

Divide both sides of the equation by 25.

y=(50/-25)x+5/25

Fifty divided by negative twenty-five is -2 because the negative sign is interchangeable in fractions. This number is in the "m" spot of y=mx+b. Therefore, negative two is your slope because b is your y-intercept, and x and y are your variables.

A line ax+by+c=0 can be put into the form y=mx+d where d is the y intercept and m is the slope.

Doing the same for 50x+25y-5=0 we get:

25y=-50x+5

=>y=(-50/25)x+(5/25)

=>y=-2x+1/2

Therefore the slope is -2

The slope m of the line ax+by +c is given by :

m = - (coefficient of x)/coeeficient of y) = -(a/b)

So the slope of the line 50x +25y - 5 is = -50/25 = -2.

50x + 25 y - 5 = 0

To find the slope we need to rewrite using the slope form which is:

y= mx + c where m is the slope.

50 x + 25 y - 5 = 0

==> 25y = -50x + 5

deivide by 25 to free y:

==> y = -50/25 + 5/25

==> y= -2x + 1/5

Then the slope is m = -2