2 Answers | Add Yours
Carbon= (24/46)*100= 52.2%
Hydrogen= 5+1=6 (6/46)*100= 13.0%
Oxygen= (16/46)*100= 34.8%
To determine the percent composition of ethanol, we need to determine the weight of each element from ethanol.
We'll write the chemical formula of ethanol: C2H5OH.
To calculate the weight of each element, we need to know how many moles of each element ethanol has. This thing could be easy determined just looking at the subscripts of each constituent element. Therefore ethanol has : 2 mols of carbon, 1 mole of oxygen and 6 mols of hydrogen.
We'll calculate the mass of these elements:
Mass of carbon: 2 mols* 12.01g/mol = 24.02 grams
Mass of oxygen: 1mol*16g/mol = 16 grams
Mass of hydrogen: 6 moles*1.01 g/mol = 6.06 grams
Now, we'll add the results to determine the mass of 1 mol of ethanol:
Mass of C2H5OH = 24.02 + 16 + 6.06 = 46.08 g
Now, we'll determine the percent composition of each element:
mass percent of C: (24.02/46.08)*100% = 52.14%
mass percent of O: (16/46.08)*100% = 34.77%
mass percent of H: (6.06/46.08)*100% = 13.15%
The requested mass percents are: 52.14% ; 34.77% ; 13.15%.
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes