Calculate the number of moles of oxygen in 2.00L at 24 degrees Celsius and 750 torr.

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First, we assume that the gas is ideal. Then, we use the ideal gas law:

`PV = nRT`

where P is the pressure, V the volume, n the number of moles, R the gas constant, and T absolute temperature.

This gives us:

`n = (PV)/(RT)`

Hence, substituting the given values:

`n = (PV)/(RT) = ((750/760)*2)/(0.08206*(24+273)) = 0.081 `

Answer is 0.081 moles of oxygen.

Note that temperature is in Kelvin, while pressure in atm (1 atm = 760 torr)

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