Calculate the number of moles of oxygen in 2.00L at 24 degrees Celsius and 750 torr.
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First, we assume that the gas is ideal. Then, we use the ideal gas law:
`PV = nRT`
where P is the pressure, V the volume, n the number of moles, R the gas constant, and T absolute temperature.
This gives us:
`n = (PV)/(RT)`
Hence, substituting the given values:
`n = (PV)/(RT) = ((750/760)*2)/(0.08206*(24+273)) = 0.081 `
Answer is 0.081 moles of oxygen.
Note that temperature is in Kelvin, while pressure in atm (1 atm = 760 torr)
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