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Calculate the molarity of NaOH if 28.2 mL of 0.150 M H2SO4 is required to neutralize...
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First, we need to write the chemical equation for this reaction:
`2 NaOH + H_2SO_4 -> Na_2SO_4 + 2 H_2O`
Looking from the balanced chemical equation, 2 moles of NaOH is required to neutralize 1 mole of H2SO4. Therefore:
`Mol es H_2SO_4 = (28.2)/(1000) L * 0.150`
`Mol es H_2SO_4 = 0.00423 mol es`
To get the moles of NaOH:
`Mol es of NaOH = (Mol es H_2SO_4)*2`
`Mol es of NaOH = (0.00423)*2 = 0.00846 mol es`
FInally, the molarity:
`Molarity = (Mol es NaOH)/(L of solution)`
`Molarity = (0.00846)/(0.035)`
Molarity = 0.242 M
Posted by jerichorayel on April 23, 2013 at 2:44 PM (Answer #1)
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