calculate the molar concentration of the concentration of a brine solution containing 225g of pure sodium chloride dissolved in 4.00l of solution?

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To solve for the concentration (in molarity) of the brine solution, we can use this formula:

`molarity = (mol es of NaCl)/(Liters of solution)`

To get the moles of any compound, divide the given mass by its molar mass.

`mol es NaCl = (225 grams NaCl)/(58.44 (grams)/(mol e))`

`mol es NaCl = 3.8501 mol es NaCl`

Finally, we can solve for the concentration of the brine solution:

`molarity = (3.8501 mol es NaCl)/(4.00 Liters of solution)`

`molarity = 0.963 (mol es)/(L)`

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