calculate the molar concentration of the concentration of a brine solution containing 225g of pure sodium chloride dissolved in 4.00l of solution?
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To solve for the concentration (in molarity) of the brine solution, we can use this formula:
`molarity = (mol es of NaCl)/(Liters of solution)`
To get the moles of any compound, divide the given mass by its molar mass.
`mol es NaCl = (225 grams NaCl)/(58.44 (grams)/(mol e))`
`mol es NaCl = 3.8501 mol es NaCl`
Finally, we can solve for the concentration of the brine solution:
`molarity = (3.8501 mol es NaCl)/(4.00 Liters of solution)`
`molarity = 0.963 (mol es)/(L)`
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