Calculate the magnitude of the linear momentum for each of the following cases

a.) a proton with mass 1.67 ×10−27 kg moving with a velocity of 6 x 106 m/s. Answer in units of kg x m/s.

b.) a 1.6 g bullet moving with a speed of 374m/s to the right. Answer in units of kg x m/s.

C.) a 8 kg sprinter running with a velocity of 11.8 m/s. Answer in units of kg x m/s.

d.) Earth (m=5.98 x 1024 kg) moving with an orbital speed equal to 29700 m/s. Answer in units of kg x m/s.

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We know that momentum is equal to mass multiplied by velocity. Therefore momentum in each of the four cases can be calculated as follows:

a)

Given: Mass = 11.67*[(10)^(-27)] kg, and velocity = 6*(10^6) m/s

Therefore: Momentum = Mass*Velocity = {1.67*[(10)^(-27)] }*[6*(10^6)] = 1.002*(10^-20) kg x m/s

b)

Given: Mass = 1.6 grams = 0.0016 kg, and velocity = 374 m/s

Therefore: Momentum = Mass*Velocity = 0.0016*374 = 0.5984 kg x m/s

c)

Given: Mass = 8 kg, and velocity = 11.8 m/s

Therefore: Momentum = Mass*Velocity = 8*11.8 = 94.4 kg x m/s

d)

Given: Mass = 5.98*10^24 kg, and velocity = 29700 m/s

Therefore: Momentum = Mass*Velocity = 5.98*10^24*29700 = 1.77606*10^29 kg x m/s =

Momentum of body is defined as the product of its mass and its velocity.So,if the mass of the body is in units of Kg, and its velocity is in meters per second or m/s, then the momentum is in units of kg m/s.

a)

Proton's momentum = proton's mass * its velocity .

=1.67*10^(-27)kg* (6*10^6)m/s= 10.02*10^(-27+6) = 10.02*10^-21 N

=1.002*10^-20 Kg m/s

b)

The bullets momentum = its mass in gram * its velocity in m/s

=1.6gram*374 m/s towards right.

=0.0016 kg*374 m/s

=0.5984 Kg m/s towards right.

c)

The momentum of the sprinter= sprinter's mass in kg* its velocity in m/s

= 8kg* 11.8 m/s

=94.4kg m/s

d)

The earth's momentum = the earth's mass in kg* earth's velocity in m/s

=(5.98*10^24 kg)*(29700m/s)

=1.77606*10^27 kg m/s

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