Calculate logarithm base 30 of 8 if lg5=a and lg3=b



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Posted on (Answer #1)

According to the logarithm change of base rule,


lg stands for log with base 10. So,



`=(3log2)/(log2+log3+log5)` ...........(i)

Again, log2=log(10/5)=log10-log5 =1-a [ since log5=a....(given)]

Now, putting the values of log2, log3 and log5 in (i) we get:

`log_(30)8` =`(3*(1-a))/(1-a+b+a)`


Hence, the required answer is `(3-3a)/(1+b)`

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