Calculate the limit of the queue an, using increasing criterion. an=sin(1!)/(n^2+1)+sin(2!)/(n^2+2)+...+sin(n!)/(n^2+n)



Asked on

1 Answer | Add Yours

giorgiana1976's profile pic

Posted on

For using the increasing criterion, we have to determine another string bn, with the general term


So, n/(n^2+n)<bn<n/(n^2+1)

lim bn= lim n/(n^2+n)=lim n/(n^2+1)=0, when n is extending to infinity.

But module (an)<bn, and lim bn=0, so lim an=0

We’ve answered 288,557 questions. We can answer yours, too.

Ask a question