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Calculate the kinetic energy of a proton which moves into a field of induction B=167mT,...

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gudeapp | Student, College Freshman | (Level 2) Honors

Posted June 30, 2009 at 7:03 PM via web

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Calculate the kinetic energy of a proton which moves into a field of induction B=167mT, on a circle with radius r=50cm.

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giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted July 7, 2009 at 1:31 AM (Answer #1)

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Lorentz force is acting on electron, so lex secunda is giving the followings:

module (q*vxB)=e*v*B=m*ac=m*v^2/r, so v=(r/m)*e*B

Ec=m*v^2/2=(e*B*r)^2/(2*m)=53.4fJ=0.334MeV

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