Calculate the kinetic energy of a proton which moves into a field of induction B=167mT, on a circle with radius r=50cm.



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Posted on (Answer #1)

Lorentz force is acting on electron, so lex secunda is giving the followings:

module (q*vxB)=e*v*B=m*ac=m*v^2/r, so v=(r/m)*e*B


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