Better Students Ask More Questions.
Calculate how many kg of lithium hydoxide must be stored on board for each day that the...
Calculate how many kg of lithium hydoxide must be stored on board for each day that the five-member crew is in flight? Help Im so confused????????????
Five member crew usually consumes 4 kg of oxygen everyday.
Cellular respiration formula: c6h12o6+6o2----> 6co2+6h2o
second equation: co2+2LiOH---> Li2Co3+H2o
1 Answer | add yours
- All reactions are complete reactions
- Only these two reactions are takes place in the system between the reactants
Once the oxygen is used by the crew `CO_2` is formed in the flight. `CO_2` is hazardous for health.So we need to remove that `CO_2` . So what is done here is forming Lithium carbonate using `CO_2` . It will remove `CO_2` from the air in flight and make a healthy environment.
Molar mass of Oxygen = 16g/mol
Amount of `O_2` consumed per day = 4kg
Amount of` O_2` moles consumed per day = `4000/32 ` = 125mol
`O_2:CO_2 = 1:1`
Amount of `CO_2` formed per day = 125mol
`CO_2+2LiOH rarr Li_2CO_3+H_2O`
`CO_2:LiOH = 1:2`
Amount of `LiOH` required per day = 125*2 = 250mol
Molar mass of `LiOH` = 24g/mol
mass of `LiOH` required `= 24*250 = 6000g = 6kg`
So for the process we need 6kg of LiOH.
Posted by jeew-m on December 17, 2012 at 2:59 AM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.