Calculate the height of cliff. Ignore air resistance.
A stunt car in a movie drives horizontally off a cliff at 26.2m/s and lands 42.5m from the base of the cliff.
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Using the horizontal movement;
`rarr S = Ut + 1/2at^2`
Since there is no acceleration in the horizontal direction;
`S = Ut`
`42.5 = 26.2*t`
` t = 1.622 `
For the vertical movement(under gravity);
`uarr S = Ut+1/2at^2`
`S = 0+1/2*9.81*1.622^2`
`S = 12.9m`
So the height of the clip is 12.9m.
The second part of the question is deleted as adviced by the administrators.
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