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Calculate the frequency if vector H = xsin(10^7pi t-0.2z)+ycos(10^7pi t-0.2z-5/2pi)?
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In the given expression for vector H, the coefficient in front of time t
is the angular frequency: `omega=10^7pi`
Angular frequency `omega` and frequency f are related by the expression
`f = omega/(2pi)`
So from here the frequency is
`f = (10^7pi)/(2pi) = 5*10^6` Hz
Posted by ishpiro on May 26, 2013 at 5:23 PM (Answer #1)
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