# Calculate the concentration in g L^-1 and the molarity of each compound.Each 200 mL of an electrolyte solution designed for treating dehydration contains 0.47 g of sodium chloride (NaCl), 0.30 g of...

Calculate the concentration in g L^-1 and the molarity of each compound.

Each 200 mL of an electrolyte solution designed for treating dehydration contains 0.47 g of sodium chloride (NaCl), 0.30 g of potassium chloride (KCl) and 3.56g of glucose (C6H12O6).

(The answer for the concentration in g L^-1 17.8 g L^-1 and the molarity is 0.9989 M)

If this is considered as me asking 2 questions at once, I just thought that because them two are questioned in my textbook in one sentence, I thought it would be okay for me to do so.

Posted on

Since molarity is defined as moles per liter, you need to first determine how many grams of each compound you would have in 1 liter.  This would be 5 times as much as in 200 mL. This calculation will also give you the concentration in grams/liter.

Second, find the formula mass of each of the three compounds:

formula mass of NaCl = atomic mass of Na + atomic mass of Cl

formula mass of KCl = atomic mass of K + atomic mass of Cl

formula mass of glucose = atomic mass of C * 6 + atomic mass of hydrogen * 12 + atomic mass of O * 6.

Now you can divide the actual mass of each compound by its formula mass to find the molarity of each compound.

Sources: