Calculate the concentration in g L^-1 and the molarity of each compound.
Each 200 mL of an electrolyte solution designed for treating dehydration contains 0.47 g of sodium chloride (NaCl), 0.30 g of potassium chloride (KCl) and 3.56g of glucose (C6H12O6).
(The answer for the concentration in g L^-1 17.8 g L^-1 and the molarity is 0.9989 M)
If this is considered as me asking 2 questions at once, I just thought that because them two are questioned in my textbook in one sentence, I thought it would be okay for me to do so.
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Since molarity is defined as moles per liter, you need to first determine how many grams of each compound you would have in 1 liter. This would be 5 times as much as in 200 mL. This calculation will also give you the concentration in grams/liter.
Second, find the formula mass of each of the three compounds:
formula mass of NaCl = atomic mass of Na + atomic mass of Cl
formula mass of KCl = atomic mass of K + atomic mass of Cl
formula mass of glucose = atomic mass of C * 6 + atomic mass of hydrogen * 12 + atomic mass of O * 6.
Now you can divide the actual mass of each compound by its formula mass to find the molarity of each compound.
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