A cable car 100m above the ground is seen to have an angle of elevation of 65 degress when it is on a bearing of 345 degress. After a minute, it has an angle of elevation of 69 degress and is on a bearing of 025 degress. Find how far it travels in that minute, and its speed in m.s^-1
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Let A be the position of cable car at 100m above the ground.
Let B the position where observer is standing. and O is point just below the the cable car
Thus AOB is right angle , and angle B is 65 degree.
Let A' be after a minute and O' be the point just below the cable car
distance travelled by cable car in 1 minute=BO-B'O'
Thus speed of the cable car=`8.24/60=0.14 ms^(-1)`
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